Mathématiques

Question

bonjour pouvez vous m aider a factoriser 30-12 ; 16x²+20x ; 9a²-3a ; 18x²-30x+36 ; x²+6x+9 ; 25x²-40x+16 ; 36x²-1 ; 9-12x+4x² ; (2x+1)(3x-1)-(2x+1)(3x+2) ; 'x-6²)+(x+3)(x-6) ; 9-(x+2)² ; x²-25-(3x+1)(x-5) ; (5x+3)(x-2)+x²-4x+4 ; (2+x²)-(4x+5)² merci beaucoup

1 Réponse

  • 30-12
    =6(5-2)

    16x²+20x
    =4x(4x+5)

    9a²-3a
    =3a(3a-1)

    18x²-30x+36
    =6(3x²-5x+6)

    x²+6x+9
    =(x+3)²

    25x²-40x+16
    =(5x-4)²

    36x²-1
    =(6x+1)(6x-1)

    9-12x+4x²
    =(3-2x)²

    (2x+1)(3x-1)-(2x+1)(3x+2)
    =
    (2x+1)(3x-1-3x-2)
    =(2x+1)(0x-3)
    =-3(2x+1)

    (x-6)²+(x+3)(x-6)
    =
    (x-6)(x-6)+(x+3)(x-6)
    =(x-6)(x-6+x+3)
    =(x-6)(2x-3)

    9-(x+2)²
    =[3-(x+2)]
    [3+(x+2)]
    =(3-x-2)(3+x+2)
    =(-x+1)(x+5)

    x²-25-(3x+1)(x-5)
    =
    (x-5)(x+5)-(3x+1)(x-5) 
    =(x-5)[x+5-(3x+1)]
    =(x-5)(x+5-3x-1)
    =(x-5)(-2x+4)
    =2(x-5)(-x+2)

    (5x+3)(x-2)+x²-4x+4
    =
    (5x+3)(x-2)+(x-2)²
    =(5x+3)(x-2)+(x-2)(x-2)
    =(x-2)(5x+3+x-2)
    =(x-2)(6x+1)

    (2+x)²-(4x+5)²
    =[
    (2+x)-(4x+5)][(2+x)+(4x+5)]
    =(2+x-4x-5)(2+x+4x+5)
    =(-3x-3)(5x+7)
    =-1(x+1)(5x+7)

Autres questions